3x^-5=(1/9)^x

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Solution for 3x^-5=(1/9)^x equation: 



3x^-5=(1/9)^x

We move all terms to the left:

3x^-5-((1/9)^x)=0



Domain of the equation: 9)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x^-((+1/9)^x)-5=0

We add all the numbers together, and all the variables

3x-((+1/9)^x)-5=0

We multiply all the terms by the denominator


3x*9)^x)-((-5*9)^x)+1=0

We add all the numbers together, and all the variables

3x*9)^x)-((-45)^x)+1=0

Wy multiply elements

27x^2-45)^x)+1=0

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